# Subset Sum

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There are traditionally two problems associated with **Subset Sum**. One is counting the number of ways a list of numbers make up a given integer. This is also referred to as the Coin Counting problem. (We will call this *Problem C* for this article.) The other is figuring out if a subset of a given list of integers can sum to a given integer (usually 0). This is, in a way, a special case of the knapsack problem. (We will call this *Problem K* for this article.)

## Problem C (Coin Counting)[edit]

The problem can be defined as: Given a set (or list) of positive integers , how many solutions does have (where for all )?

Let be the number of ways to sum to using the subsequence , then the recurrence is simply:

where

This problem is often asked as a variation of such: Given 1c, 2c, 5c, and 10c pieces, how many ways can you make a dollar?

## Problem K (Simplified Knapsack)[edit]

This problem can be thought of as a more specific version of *Problem C*. It can be defined as:
Given a set (or list) of positive integers , is there a solution such that (where )? This is basically a decision variation on *Problem C*, and can be solved similarly.

The recurrence is essentially:

where

Given a set of non-negative integers, and a value sum, determine if there is a subset of the given set with sum equal to given sum.

Examples: set[] = {3, 34, 4, 12, 5, 2}, sum = 9 Output: True //There is a subset (4, 5) with sum 9. Let isSubSetSum(int set[], int n, int sum) be the function to find whether there is a subset of set[] with sum equal to sum. n is the number of elements in set[].

The isSubsetSum problem can be divided into two subproblems …a) Include the last element, recur for n = n-1, sum = sum – set[n-1] …b) Exclude the last element, recur for n = n-1. If any of the above the above subproblems return true, then return true.

Following is the recursive formula for isSubsetSum() problem.

isSubsetSum(set, n, sum) = isSubsetSum(set, n-1, sum) || isSubsetSum(set, n-1, sum-set[n-1])

Base Cases:

isSubsetSum(set, n, sum) = false, if sum > 0 and n == 0 isSubsetSum(set, n, sum) = true, if sum == 0

## Other variations[edit]

There are still other variations and constraints that can be solved similarly. A constraint where is one such example.